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    <script>
        //柯里化思想

        //请实现以下效果
        function add(a, b, c) {
            return a + b + c
        }
        // console.log(add.length);

        const res = add(1, 2, 3) //6

        

        // function curry (a){
        //     return function(b){
        //         return function(c){
        //             return a+b+c
        //         }
        //     }
        // }

        
        // console.log(curry(1)(2)(3));
        const addCurry = curry(add);

        function curry (func){
            return function curried(...args) {
                if (args.length >= func.length) { // (1)
                    return func(...args);
                } else {
                    return function(...args2) { // (2)
                        return curried(...args.concat(args2));
                    }
                }
            };
        }
        console.log(addCurry(1)(2)(3));

        // addCurry >> curry(add) >> curried(1) >> function(2) >> curried(1,2) >> function(3) >> curried(1,2,3)
        //>> add(1,2,3) >> a+b+c


            // const curry = (fn) => (a , b , c)=> fn(1,2,3);  //fn(1,2,3) == add(1,2,3)
            // console.log(addCurry(2, 3, 5));

            // const curry = (fn) =>(a,b) => c => fn(1,2,3);  //fn(1,2,3) == add(1,2,3)
            // console.log(addCurry(1, 2)(3));

            // const curry = (fn) => a => (b,c) => fn(1,2,3);  //fn(1,2,3) == add(1,2,3)
            // console.log(addCurry(1)(2, 3));

            // const curry = (fn) => a => b => c => fn(1, 2, 3);  //fn(1,2,3) == add(1,2,3)
            // console.log(addCurry(1)(2)(3));









        //要求声明一个curry函数，函数add经过curry函数的处理后，每次调用只能接收一个参数
        // const curry = () => { }


        // let addCurry = curry(add)

        // // console.log(addCurry);
        // const res2 = addCurry(1)(2)(3) //6

        // console.log(res2);
    </script>
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